Precalculus. Solve for ? sin (2x)=-1/2. sin(2x) = − 1 2 sin ( 2 x) = - 1 2. Take the inverse sine of both sides of the equation to extract x x from inside the sine. 2x = arcsin(−1 2) 2 x = arcsin ( - 1 2) Simplify the right side. Tap for more steps 2x = − π 6 2 x = - π 6. Divide each term in 2x = − π 6 2 x = - π 6 by 2 2 and
Drawing the right angled triangle, you realise that length of opposite side =2 and length of hypotenuse =3 \Rightarrow length of adjacent side = sqrt3^2-2^2=sqrt5 Thus tan sin^-1 2/3=opposite/adjacent=2/sqrt5
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sin 1 2 akar 3
